1. A quadrilateral has vertices A(0,0), B(8,0),C(7,5), and D(3,5). 40 points b. Find the length of each side to the nearest tenth

Question

1. A quadrilateral has vertices A(0,0), B(8,0),C(7,5), and
D(3,5). 40 points
b. Find the length of each side to the nearest tenth of a
unit.​

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Remi 2 weeks 2021-11-25T08:43:19+00:00 1 Answer 0

Answers ( )

    0
    2021-11-25T08:45:06+00:00

    The formula for the distance between two points is

    d(A,B) = \sqrt{(A_x-B_x)^2+(A_y-B_y)^2}

    Note that, if two points have one coordinate in common, this formula simplifies to

    d(A,B) = |A_x-B_x|,\quad d(A,B)=|A_y-B_y|

    (the first if they share the y coordinate, the second if they share the x coordinate).

    So, these are the lengths of the sides:

    d(A,B)=|8-0|=8

    (because they share the y coordinate)

    d(B,C) = \sqrt{(8-7)^2+(0-5)^2}=\sqrt{1+25}=\sqrt{26}

    (standard formula)

    d(C,D)=|7-3|=4

    (because they share the y coordinate)

    d(A,D) = \sqrt{(0-3)^2+(0-5)^2}=\sqrt{9+25}=\sqrt{34}

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