10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then random

Question

10 cards are numbered from 1 to 10 and placed in a box. One card is
selected at random and is not replaced. Another card is then randomly
selected. What is the probability of selecting two numbers that are less than
62​

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Delilah 1 week 2021-09-15T03:43:04+00:00 1 Answer 0

Answers ( )

    0
    2021-09-15T03:44:59+00:00

    Answer:

    0.889

    Step-by-step explanation:

    I think it is multiplied.

    10 *9 = 90

    which is the total number of ways you can draw 2 cards without replacement.

    I think it is easier to figure out how many possibilities there are over 62 and go from there.

    10*9

    10*8

    10*7

    ===========

    9*8

    9*7

    So there are 5 combinations that are over 62. There are 5 more possibilities because you could draw them in the reverse order

    9 * 10

    8 * 10

    7 * 10  

    8* 9

    7 * 9

    In all there are 10 ways of drawing numbers that are over 62

    So what is the probability of drawing 2 cards above 62?

    10/90 = 1/9 = 0.111

    Therefore, there must be a probability of 1 – 0.111 for under 62 = 0.889

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