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## 3 years ago the sum of ages of father and his son was 54 years. After 3 years the father’s age will be double age of son’s age after 9 years

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## Answers ( )

x+y= 54

x+3= 2(y+9) –

multiply the bracket by 2x+3 = 2y+18

x+3-3= 2y+18-3

x= 2y+15

x-2y= 15

x+y= 54

x-x-2y+-y= 15-54

-2y-y= – 39

-3y=-39

Divide by -3 for -3y and -39-3y/-3= -39/-3

y = 13 ( son)Use substitution methodtofindxx+y= 54

x+13= 54

x+13-13= 54-13 (

moving +13 to -13 to the other side)x= 41 ( father)Answer is father is 41 years old -xAnswer is father is 41 years old -xSon is 13 years old -yAnswer:

Father is 41 years old and son is 13 years old.

Step-by-step explanation:

Set father is x years old, and son is y years old 3 years ago.

x+y=54

x+3=2(y+9) x+3=2y+18

x+y=54

-) x-2y=15

———————

3y=39 y=13, x=41