3 years ago the sum of ages of father and his son was 54 years. After 3 years the father’s age will be double age of son’s age after 9 years

Question

3 years ago the sum of ages of father and his son was 54 years. After 3 years the father’s age will be double age of son’s age after 9 years. Find the present ages of father and son.​

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Lyla 1 week 2021-09-15T21:28:36+00:00 2 Answers 0

Answers ( )

    0
    2021-09-15T21:29:39+00:00

    x+y= 54

    x+3= 2(y+9) – multiply the bracket by 2

    x+3 = 2y+18

    x+3-3= 2y+18-3

    x= 2y+15

    x-2y= 15

    x+y= 54

    x-x-2y+-y= 15-54

    -2y-y= – 39

    -3y=-39

    Divide by -3 for -3y and -39

    -3y/-3= -39/-3

    y = 13 ( son)

    Use substitution method to find x

    x+y= 54

    x+13= 54

    x+13-13= 54-13 ( moving +13 to -13 to the other side)

    x= 41 ( father)

    Answer is father is 41 years old -x

    Answer is father is 41 years old -xSon is 13 years old -y

    0
    2021-09-15T21:30:32+00:00

    Answer:

    Father is 41 years old and son is 13 years old.

    Step-by-step explanation:

    Set father is x years old, and son is y years old 3 years ago.

    x+y=54

    x+3=2(y+9) x+3=2y+18

    x+y=54

    -) x-2y=15

    ———————

    3y=39 y=13, x=41

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