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## 6.(08.04) What is the sum of the geometric sequence 2, 8, 32, … if there are 8 terms?

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## Answers ( )

Answer:43,690.Step-by-step explanation:The common ratio

ris 8/2 = 32/8 =4.Sum of n terms = a1 * (r^n – 1) / (r – 1).

a1 = 2 and r = 4 so

Sum of 8 terms = 2 *(4^8 – 1) / (4 – 1)

= 2 * 65535 / 3

= 43,690.