6.(08.04) What is the sum of the geometric sequence 2, 8, 32, … if there are 8 terms?

Question

6.(08.04)
What is the sum of the geometric sequence 2, 8, 32, … if there are 8 terms?

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Aaliyah 6 days 2021-09-15T00:05:47+00:00 1 Answer 0

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    2021-09-15T00:07:30+00:00

    Answer:

    43,690.

    Step-by-step explanation:

    The common ratio r is 8/2 = 32/8 = 4.

    Sum of n terms = a1 * (r^n – 1) / (r – 1).

    a1 = 2 and r = 4 so

    Sum of 8 terms = 2 *(4^8 – 1) / (4 – 1)

    = 2 * 65535 / 3

    = 43,690.

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