A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the paper and yo

Question

A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the paper and you get 1.50 inches. What is the actual part size in inches? A. 6.0 B. 1.5 C.4.0 D 375

in progress 0
Kylie 2 weeks 2021-09-09T11:34:51+00:00 1 Answer 0

Answers ( )

    0
    2021-09-09T11:36:26+00:00

    Answer:

    A. 6.0

    Step-by-step explanation:

    We have been given that the the inside diameter of the part on the paper is 1.50 inches.

    We have been given that scale is 4:1 for actual size to drawing side.

    \text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=\frac{4}{1}

    Upon substituting 1.50 in our given proportion, we will get:

    \frac{\text{Actual size}}{1.50\text{ inches}}=\frac{4}{1}

    \frac{\text{Actual size}}{1.50\text{inches}}\times 1.50\text{ inches}=\frac{4}{1}\times 1.50\text{ inches}

    \text{Actual size}=4\times 1.50\text{ inches}

    \text{Actual size}=6.0\text{ inches}

    Therefore, the actual size is 6.0 inches and option A is the correct choice.

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )