A chemist needs 70 milliliter of 29% solution but has only 19% and 33% solutions available. Find how many milliliter of each that should be

Question

A chemist needs 70 milliliter of 29% solution but has only 19% and 33% solutions available. Find how many milliliter of each that should be mixed to get the desired solution

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6 days 2021-10-13T04:01:05+00:00 1 Answer 0

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    2021-10-13T04:02:26+00:00

    Answer:

    • 50 mL of 33%
    • 20 mL of 19%

    Step-by-step explanation:

    Let x represent the volume in mL of 33% solution needed. Then 70-x is the volume of 19% solution required. The total amount of solute is …

      0.33x + 0.19(70 -x) = 0.29(70)

      0.14x = 70(0.29 -0.19)

      x = 70(0.10/0.14) = 50

    50 mL of 33% solution should be mixed with 20 mL of 19% solution to get the desired mix.

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