A coffee pot in the form of a circular cylinder of radius 2 in. is being filled with water flowing at a constant rate. If the water level is

Question

A coffee pot in the form of a circular cylinder of radius 2 in. is being filled with water flowing at a constant rate. If the water level is rising at the rate of 0.9 in./s, what is the rate (in in3/s) at which water is flowing into the coffee pot? (Round your answer to one decimal place.)

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Gianna 7 days 2021-10-12T08:18:59+00:00 1 Answer 0

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    2021-10-12T08:20:45+00:00

    Answer:

    11.3 in^3/s

    Step-by-step explanation:

    Water level rising rate = 0.9 in/s

    The cross-sectional area of the coffee pot is given by;

    A= \pi r^2\\A = \pi 2^2\\A= 12.5664\ in^2

    The rate at which water is flowing into the coffee pot is given by the product of the cross-sectional area by the rate at which the level rises:

    R_{v} = 12.5664\ in^2 * 0.9\ in/s \\R_{v} = 11.3 \ in^3/s

    Water flows into the coffee pot at 11.3 in^3/s

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