A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by h(x)=-(x-11)(x+3)h(x)=−(x−11)(x+3)h

Question

A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by h(x)=-(x-11)(x+3)h(x)=−(x−11)(x+3)h, left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 11, right parenthesis, left parenthesis, x, plus, 3, right parenthesis How many seconds after takeoff will the hovercraft land on the ground?

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Ella 4 days 2021-10-10T21:23:57+00:00 2 Answers 0

Answers ( )

    0
    2021-10-10T21:25:34+00:00

    Answer:

    After 11 seconds the hovercraft will land on ground

    Step-by-step explanation:

    Given function that shows the height of a hovercraft,

    h(x) = -(x-11)(x+3)

    Where,

    x = number of second.

    When the hovercraft land the ground,

    h(x) = 0

    -(x-11)(x+3)=0

    \implies (x-11)(x+3)=0

    By zero product property,

    x – 11 = 0 or x + 3 = 0

    ⇒ x = 11 or x = -3 ( not possible ),

    Hence, after 11 seconds the hovercraft will land on ground.

    0
    2021-10-10T21:25:35+00:00

    at the time I am writing this the other answer only has a 3.2 rating, but I can vouch that the answer is still correct: 11 seconds !

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