A particle moves along the curve y=7 x 2+4y=7 x 2+4 in such a way that its xx-coordinate is changing at a rate of −5−5 centimeters per secon

Question

A particle moves along the curve y=7 x 2+4y=7 x 2+4 in such a way that its xx-coordinate is changing at a rate of −5−5 centimeters per second. At what rate is the particle’s yy-coordinate changing when the particle is at the point where x=1x=1?

in progress 0
Skylar 1 week 2021-10-11T18:55:40+00:00 1 Answer 0

Answers ( )

    0
    2021-10-11T18:57:30+00:00

    Answer:

    The y-coordinate is changing by the rate of -70 cm per sec.

    Step-by-step explanation:

    Given equation,

    y = 7x^2 + 4

    Differentiating with respect to time (t),

    \frac{dy}{dt}=14x \frac{dx}{dt}

    We have,

    \frac{dx}{dt}=-5\text{ cm per sec}, x = 1

    \frac{dy}{dt} = 14(1)(-5)=-70\text{ cm per sec}

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )