## A piggy bank contains some dimes and nickels. There are 8 more dimes than nickels in the bank. There is a total of $1.40. How many of each t Question A piggy bank contains some dimes and nickels. There are 8 more dimes than nickels in the bank. There is a total of$1.40. How many of each type of coin are in the bank?

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1 week 2021-09-15T04:29:22+00:00 2 Answers 0

1. This question is solved using a system of equations. I am going to say that:

• x is the number of dimes.
• y is the number of nickels.

Doing this, we get that: There are 4 nickels and 12 dimes.

There are 8 more dimes than nickels in the bank.

This means that: There is a total of $1.40. • Nickel is worth$0.05.
• Dime is worth \$0.1.

Thus, for the nickels: Since      For the dimes: There are 4 nickels and 12 dimes.

A similar question is found at https://brainly.com/question/24342899

4 nickels

12 dimes

Step-by-step explanation:

Dimes are worth .1 each while nickels are .05 each.

We have 8 more dimes than nickels. Let d represent number of dimes and n for number of nickels. This means we have d=8+n.

If all our nickels and dimes together are worth 1.4 then we have another equation .1d+.05n=1.4

Lets put our equations together:

d=8+n

.1d+.05n=1.4

‐—————–Plug first equation into second.

.1(8+n)+.05n=1.4

Distribute

.8+.1n+.05n=1.4

Combine like terms

.8+.15n=1.4

Subtract .8 on both sides

.15n=.6

Divide both sides by .15

n=.6/.15=4

Remember there are 8 more dimes so d=8+4=12.