A researcher wanted to determine whether certain accidents were uniformly distributed over the days of the week. The data show the day of th

Question

A researcher wanted to determine whether certain accidents were uniformly distributed over the days of the week. The data show the day of the week for nequals303 randomly selected accidents. Is there reason to believe that the accident occurs with equal frequency with respect to the day of the week at the alphaequals0.05 level of​ significance?

in progress 0
Charlie 2 weeks 2021-09-10T21:49:55+00:00 1 Answer 0

Answers ( )

    0
    2021-09-10T21:51:08+00:00

    Answer:

    Chi-square = 4.600

    Degrees of freedom= 6

    there is no evidence to reject hypothesis.

    Step-by-step explanation:

    H₀ : uniformly distributed

    H₁: not uniformly distributed                            

    Suppose some value of observed or expected frequency  

    Observed frequency : 39 40 30 40 41 49 41     Total: 280

    Expected frequency  :  40 40 40 40 40 40 40  Total: 280


    Calculated the chi-square value

    Chi-square = sigma {(O-E)^2/E}

    = 0.025+0.000+2.500+0.000+0.025+2.025+0.025  

     4.600

    Degrees of freedom=d f = n-1 = 7-1 = 6

    Chi-square for 6 d.f at alpha = 0.05 is 12.59

    Chi-square of calculated value < its critical value at alpha = 0.05, we see that there is no evidence to reject hypothesis.

    The frequency of Sat is wrongly taken as 41 instead of 51

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )