A survey given to consumers leaving a supermarket three days before Thanksgiving asked whether turkey would be part of the Thanksgiving meal

Question

A survey given to consumers leaving a supermarket three days before Thanksgiving asked whether turkey would be part of the Thanksgiving meal. Of the 182 people surveyed, 26 said “no.” Give a 95% confidence interval for the population proportion who claimed not to be eating turkey.

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Sadie 1 week 2021-11-22T02:51:04+00:00 1 Answer 0

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    2021-11-22T02:52:51+00:00

    Answer:

    (0.1392,0.1466)

    Step-by-step explanation:

    Given that a survey given to consumers leaving a supermarket three days before Thanksgiving asked whether turkey would be part of the Thanksgiving meal

    People surveyed = 182

    claimed not eating turkey = 26

    Sample proportion = \frac{26}{182} \\=0.1429

    Std error =\sqrt{\frac{pq}{n} } \\=0.0260

    Margin of error = 1.96*SE=0.00378

    Confidence interval = (0.1429-0.0037,0.1429+0.0037)\\=(0.1392,0.1466)

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