A triangle has side lengths 6, 7, and B, and the angle between the sides of lengths 6 and 7 measures 60 degress. If A si the area of the tri

Question

A triangle has side lengths 6, 7, and B, and the angle between the sides of lengths 6 and 7 measures 60 degress. If A si the area of the triangle and B is the integer closet B, find the value of A/b.

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Abigail 2 weeks 2021-09-11T00:14:46+00:00 1 Answer 0

Answers ( )

  1. The value of A/b is 2.60

    Step-by-step explanation:

    We have cosine formula

               c² = a² + b² – 2ab cosC

    Here

              c = B

              a = 6

              b = 7

              C = 60°

    Substituting

              B² = 6² + 7² – 2 x 6 x 7 cos60

              B² = 43

              B = 6.56

               b = 7 closest integer to B.

    Given that A is area of triangle

              A=0.5absinC

              A = 0.5 x 6 x 7 x sin60 = 18.19

    We need to find \frac{A}{b}

            \frac{A}{b}=\frac{18.19}{7}=2.60

    The value of A/b is 2.60      

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