According to the​ label, a can of soup holds an average of 307 ​grams, with a standard deviation of 4.1 grams. Assuming a normal​ distributi

Question

According to the​ label, a can of soup holds an average of 307 ​grams, with a standard deviation of 4.1 grams. Assuming a normal​ distribution, what is the probability that a can will be sold that holds more than 308 ​grams?

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Ella 2 weeks 2021-09-13T15:37:51+00:00 1 Answer 0

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    2021-09-13T15:38:59+00:00

    Answer: 0.4052

    Step-by-step explanation:

    Given : Mean : \mu=\text{307 ​grams}

    Standard deviation : \sigma = \text{4.1 grams}

    The formula for z -score :

    z=\dfrac{x-\mu}{\sigma}

    For x=308 ,

    z=\dfrac{308-307}{4.1}=0.24390\approx0.24

    The p-value = P(z>0.24)=1-P(z<0.24)

    =1-0.5948348= 0.4051652\approx0.4052

    Hence, the probability that a can will be sold that holds more than 308 ​grams =0.4052.

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