An arrow is shot vertically upward from a platform 16ft high at a rate of 190ft/sec. When will the arrow hit the ground? Use the formula:

Question

An arrow is shot vertically upward from a platform 16ft high at a rate of 190ft/sec. When will the arrow hit the ground? Use the formula: h=−16t²+vt+h0. (Round your answer to the nearest tenth.)

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Claire 6 days 2021-09-10T10:44:38+00:00 2 Answers 0

Answers ( )

    0
    2021-09-10T10:45:52+00:00

    h(t) = -16t2 + 186t + 43

    at the ground h = 0

    hence; -16t2 + 186t + 43 = 0

    solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 – 4ac)1/2)/2a

    gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)

    0
    2021-09-10T10:46:22+00:00

    Answer:

    time required for arrow  to reach ground is 10.8  sec

    when  t = 10.8 seconds to the nearest tenth

    Step-by-step explanation:

    Given values are  

    Velocity = 190 ft/sec                     height = 16 ft

    Given formula is  

    h=−16t²+vt+h0

    adding the values, we get

    h(t)= -16t²+190t+16

    so we have to find when the hit he ground, so at ground the height will be 0  

    0= -16t²+190t+16

    -16t²² + 190t + 16= 0  

     

    using the quadratic formula

    x = (-b +(b2 – 4ac)1/2)/2a

    values  

    a = -16, b = 190, c = 16

    x= -190 + ((-190)²- 4 (-16)(16) ½ / 2(-16)

    x= -190 + ((-190) ²+1024) ½ / 2(-16)

    x= -190+ (-190²+ 32²) ½ /-32

    taking under root  

    x= -190  + ( -190+32)/ -32

    x= 190 + (-158)/-32

    we have   2 options,

    x= 190 + (-158)/-32                       x= 190 – (-158)/-32

    x= 190 -158)/-32                         x= 190 +158)/-32

    x= -1                                           x= 10.875  

    or t = 10.875

    so the negative root has no practical significance  

    and we have t = 10.8 seconds to the nearest tenth  

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