Can someone please help me Factor 4x^2 – 81

Question

Can someone please help me Factor 4x^2 – 81

in progress 0
Brielle 3 days 2021-10-11T00:08:46+00:00 2 Answers 0

Answers ( )

    0
    2021-10-11T00:10:12+00:00

    The answer is (2x-9)(2x+9)

    4x^2-81
    2^2 x^2-9^2
    (2x)^2-9^2
    (2x-9)(2x+9)

    0
    2021-10-11T00:10:21+00:00

    Answer:

    (2x-9)(2x+9)

    Step-by-step explanation:

    This is a difference of squares because it can be written as (2x)^2-9^2

    The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)

    So replace a with 2x and b with 9 giving us

    4x^2-81=(2x-9)(2x+9)

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )