Describe the nature of the roots for this equation. 3x^2+x-5= 0

Question

Describe the nature of the roots for this equation.
3x^2+x-5= 0

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Aubrey 2 weeks 2021-09-13T13:12:59+00:00 2 Answers 0

Answers ( )

    0
    2021-09-13T13:14:37+00:00

    Answer:

    two real,irrational roots.

    GOOD LUCK!

    Step-by-step explanation:

    0
    2021-09-13T13:14:52+00:00

    Answer:

    This equation has no natural roots.

    Step-by-step explanation:

    3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=\dfrac{-1\pm\sqrt{61}}{(2)(3)}=\dfrac{-1\pm\sqrt{61}}{6}\notin\mathbb{N}

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