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## Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as f

Question

Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

shock resistance

scratch resistance high low

high 70 9

low 16 5

Let A denote the event that a disk has high shock resistance, and let B denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Input your answers in the fractional form (do not simplify).

P(A)

P(B)

P(A’)

P(A U B)

P(A’ U B)

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2 weeks
2021-09-14T21:09:16+00:00
2021-09-14T21:09:16+00:00 1 Answer
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## Answers ( )

Answer:

P(A) = 86/100

P(B) = 79/100

P(A’) = 14/100

P(A U B) = 95/100

P(A’ U B) = 84/100

Step-by-step explanation:

i. P(A) = number of disks with high shock resistance/total number of disks

= (70+16)/100

= 86/100

ii. P(B) = number of disks with high scratch resistance/total number of disks

= (70+9)/100

= 79/100

iii. P(A’) = number of disks without high shock resistance/total number of disks

= (100-86)/100

= 14/100

iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks

= (70+9+16)/100

= 95/100

v. P(A’UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks

= (5+9+70)/100

= 84/100