Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydiver falls 64ft

Question

Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydiver falls 64ft in 2 seconds, how far will he fall in 10 seconds

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Eva 2 weeks 2021-09-09T13:17:14+00:00 1 Answer 0

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    2021-09-09T13:18:40+00:00

    Answer:

    The skydiver will fall 1600 ft in 10 seconds.

    Step-by-step explanation:

    Distance a body falls from rest varies directly as the squares of the time it falls

    Let distance = s    

          time = t

    Therefore , s = k  \times t^{2}

    Given, the body falls 64 ft in 2 seconds.

    Substituting in above equation,

    64 = k  \times (2)^{2}

    64 = k  \times (4)

     k  = \frac{64}{4}

     k = 16 ft/s^{2}

    We have to find how much he will fall in 10 seconds.

    s = k  \times t^{2}

    s = 16 \times 10^{2}

    s = 16 \times 100

    s = 1600 ft

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