During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of i

Question

During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played?

in progress 0
2 weeks 2021-10-11T21:49:20+00:00 1 Answer 0

Answers ( )

    0
    2021-10-11T21:50:24+00:00

    Answer: 150

    Step-by-step explanation:

    Let x be the  total number of games that the team played.

    Given : During a certain season, a team won 80 percent of its first 100 games and 50 percent of its remaining games.

    No. of games won out of first 100 games =0.80(100)               (1)

    Remaining games = x-100

    No. of games won out of remaining games=0.50(x-100)                   (2)

    If the team won 70 percent of its games for the entire season ,

    Number of games won by team = 0.70x

    Then According to the given question , we have

    No. of games won by team= No. of games won out of first 100 games + No. of games won out of remaining games

    0.80(100)+0.50(x-100)=0.70x\ \ \\\\\Rightarrow\ 80+0.5x-50=0.7x\\\\\Rightarrow\ 0.7x-0.5x=30\\\\\Rightarrow\ 0.2x=30\\\\\Rightarrow\ x=\dfrac{30}{0.2}=150

    Hence, the total number of games that the team played= 150

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )