equation of the circle with center 2,1 and 5,2 a point on the circle

Question

equation of the circle with center 2,1 and 5,2 a point on the circle

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Liliana 2 weeks 2021-11-25T01:07:55+00:00 2 Answers 0

Answers ( )

  1. Charlotte
    0
    2021-11-25T01:09:45+00:00

    Answer: (x-2)^2+(y-1)^2=10

    Step-by-step explanation:

    r=√(x-h)^2+(y-k)^2

    r=√(5-2)^2+(2-1)^2

    r=√3^2+1^2

    r=√9+1

    r=√10

    X^2+y^2=r^2

    (x-2)^2+(y-1)^2=(√10)^2

    (x-2)^2+(y-1)^2=10

  2. Charlotte
    0
    2021-11-25T01:09:46+00:00

    Answer:

    Step-by-step explanation:

    The center tells you how to handle the left side of a circle’s equation.

    (x – 2)^2 + (x – 1)^2 = r^2

    The point (5,2) gives you enough information to find r^2

    x = 5

    y = 2

    (5 – 2)^2 + (2 – 1)^2 = r^2

    (3)^2 + 1^2 = r^2

    9 + 1 = r^2

    r^2 = 10

    Complete equation

    (x – 2)^2 + (y – 1)^2 = 10

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