Evaluate the sum or explain why it diverges: Sigma^infinity_k = 3(-3/2)^k

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Evaluate the sum or explain why it diverges: Sigma^infinity_k = 3(-3/2)^k

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Reagan 17 mins 2021-09-12T07:48:58+00:00 1 Answer 0

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    2021-09-12T07:50:56+00:00

    Answer:

    Step-by-step explanation:

    Remember that in the geometric serie if | r | < 1 the serie converges and if | r | ≥1 the serie diverges.

    I suppose that the serie starts at 0, so using the geometric serie with r = | \frac{-3}{2} | > 1 the serie diverges.

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