Every evening jenna empties her pockects and puts her change in a jar. one week she had 38 coins, all of them dimes and quarters. when she a

Question

Every evening jenna empties her pockects and puts her change in a jar. one week she had 38 coins, all of them dimes and quarters. when she added them up she had a total of 6.95Every evening jenna empties her pockects and puts her change in a jar. one week she had 38 coins, all of them dimes and quarters. when she added them up she had a total of 6.95

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Adalyn 2 weeks 2021-10-13T22:17:51+00:00 1 Answer 0

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    2021-10-13T22:19:18+00:00

    Answer:

    17 dimes, 21 quarters

    Step-by-step explanation:

    I suppose you want to know how many dimes and quarters she had in her jar.

    Let’s say x = dimes and y = quarters.

    We can make the following 2 equations:

    1) x + y = 38 (number of coins in the jar)

    2) 10x + 25y = 695 (a number of dimes plus a number of quarters sum up to 695 cents)

    From 1), we can isolate y: y = 38 – x, and place that value in the second equation:

    10x + 25y = 695

    10x + 25 (38 – x) = 695

    10x + 950 – 25x = 695, then we subtract 950 on both sides and simplify

    -15x = -255

    x = 17

    So, Jenna had 17 dimes.

    y = 38 – x, so y = 38 – 17 = 21

    And she had 21 quarters.

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