Farmer Dave harvested his corn. He stored 5/9 of his corn in one large silo and 3/4 of the remaining corn in a small silo. The rest was take

Question

Farmer Dave harvested his corn. He stored 5/9 of his corn in one large silo and 3/4 of the remaining corn in a small silo. The rest was taken to market to be sold. What fraction of the corn was stored in the small silo

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Madelyn 2 weeks 2021-09-12T10:08:09+00:00 1 Answer 0

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    2021-09-12T10:09:40+00:00

    Answer:

    The amount stored in small silo are \frac{1}{3}

    Step-by-step explanation:

    It is given that He stored \frac{5}{9} of his corn in one large silo and \frac{3}{4} of remaining in small silo.

    Since \frac{5}{9} is removed, remaing is \frac{4}{9} ( 1- \frac{5}{9})

    \frac{3}{4} of remaining means,

    = (\frac{3}{4})(\frac{4}{9})

    = \frac{1}{3}

    Thus total is \frac{1}{3} + \frac{5}{9} = \frac{8}{9}

    taken to market is (1 – \frac{8}{9}) = \frac{1}{9}

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