Find all values of k for which the equation 3×2−(k+2)x+k−1=0 has no solutions.

Question

Find all values of k for which the equation 3×2−(k+2)x+k−1=0 has no solutions.

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Alexandra 2 weeks 2021-11-20T18:47:45+00:00 1 Answer 0

Answers ( )

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    2021-11-20T18:49:17+00:00

    Answer:

    there are solutions for all values of k

    Step-by-step explanation:

    In order for there to be no real solutions, the value of the discriminant must be negative. For this equation, the discriminant is …

    (-(k+2))^2 -4(3)(k-1)

    We want to find values of k for which this is negative:

    (k^2 +4k +4) -12k +12 < 0

    k^2 -8k +16 < 0

    (k -4)^2 < 0

    A square is never negative, so there are no values of k that result in the equation having no solutions.

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