find the distance from the point (1,2) to the line y=2x-1

Question

find the distance from the point (1,2) to the line y=2x-1

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Alice 1 week 2021-09-15T22:34:58+00:00 1 Answer 0

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    2021-09-15T22:36:20+00:00

    Answer:

    distance = \frac{\bf 1}{\sqrt{\bf 5}} units

    Step-by-step explanation:

    distance = \frac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}

    Given equation is y=2x-1

    it can be written as 2x-y-1=0

    here a=2, y=-1, c=-1 and the point (x_0, y_0) is (1, 2)

    distance = \frac{|2(1)+(-1)(2)-1|}{\sqrt{2^2+1^2}}

    distance = \frac{|2-2-1|}{\sqrt{4+1}}

    distance = \frac{|-1|}{\sqrt{5}}

    distance = \frac{1}{\sqrt{5}} units

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