Find the minimum or maximum y-value for f(x)=3x^2 + 12x + 8. Question Find the minimum or maximum y-value for f(x)=3x^2 + 12x + 8. in progress 0 Math Mackenzie 1 week 2021-09-15T17:52:02+00:00 2021-09-15T17:52:02+00:00 1 Answer 0

## Answers ( )

Finding x:

x = – b / 2a, where b is the coefficient of the x term and a is the coefficient of the x2 term.

x = – 12 / (2 * 3)

x = -2

Finding y:

To find y, substitute for x in the given function

y = 3 * (-2)2 + 12 * (-2) + 4

y = 12 – 24 + 4

y = -16

Vertex:

The vertex is (-2, -16)

Since the coefficient of the x2 term is positive, we have a minimum.

The minimum is at -16.

Your answer:

MIN,-16