Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20,0).

Question

Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20,0).

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Everleigh 2 weeks 2021-09-14T21:58:03+00:00 1 Answer 0

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    2021-09-14T21:59:33+00:00

    Answer:

    The point M is (10,7.5).

    Step-by-step explanation:

    Given:

    AB is in a ratio of 5:5. A is at (0, 15) and B is at (20,0).

    Now, to find the point M that divides the segment AB.

    The points are A (0,15) and B (20,0) of the segment AB, which divides the point into m_{1}andm_{2} .

    So, m_{1}=5,m_{2}=5.

    A= (x_{1},y_{1} )(0,15) and B=(x_{2},y_{2})(20,0)

    So, by putting the formula to find M.

    x= \frac{m_{1} x_{2}+m_{2}x_{1}} {m_1+m_2}

    x= \frac{5\times 20+5\times 0}{5+5}

    x= \frac{100}{10}

    x=10

    y= \frac{m_{1} y_{2}+m_{2}y_{1}} {m_1+m_2}

    y= \frac{5\times 0+5\times 15}{5+5}

    y= \frac{75}{10}

    y=7.5

    So, the required point is (x,y)=(10,7.5)

    Therefore, the point M is (10,7.5).

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