Find the value of x so that the line passing through (x, 10) and (-4, 8) has a slope of 2/3. Thanks yall!

Question

Find the value of x so that the line passing through (x, 10) and (-4, 8) has a slope of 2/3.

Thanks yall!

in progress 0
Melanie 4 days 2021-10-10T21:42:50+00:00 2 Answers 0

Answers ( )

    0
    2021-10-10T21:44:09+00:00

    Answer:

    x = – 1

    Step-by-step explanation:

    Using the slope formula to find the slope m

    m = (y₂ – y₁ ) / (x₂ – x₁ )

    with (x₁, y₁ ) = (x , 10) and (x₂, y₂ ) = (- 4, 8)

    m = \frac{8-10}{-4-x} = \frac{2}{3}, that is

    \frac{-2}{-4-x} = \frac{2}{3} ( cross- multiply )

    2(- 4 – x) = – 6 ( divide both sides by 2 )

    – 4 – x = – 3 ( add 4 to both sides )

    – x = 1 ( multiply both sides by – 1 )

    x = – 1

    0
    2021-10-10T21:44:36+00:00

    Answer:

    x=-1

    Step-by-step explanation:

    General equation of line is y=mx+n where m is slope. So, if we use point (-4, 8) and slope in equation we have 8= 2/3.(-4)+n

    Then we have n=8+8/3, that is n=32/3

    Therefore equation of our line is y=2/3.x + 32/3

    For the point (x,10) in equation 10=2/3.x + 32/3

    Then we have 2/3.x = – 2/3 then x= -1

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )