Find the values for c and d that would make the following equation true. (cy^2)(4y^d)=-20y^3 Question Find the values for c and d that would make the following equation true. (cy^2)(4y^d)=-20y^3 in progress 0 Math Serenity 1 week 2021-11-26T04:31:49+00:00 2021-11-26T04:31:49+00:00 1 Answer 0

## Answers ( )

Answer:c = -5 and d = 1

Step-by-step explanation:First, multiply out (cy^2)(4y^d). We get: 4cy^(2+d).

We equate this result to the right side of the equation: – 20y^3.

Then, equating the exponents and solving for d, we get: 2 + d = 3, or

d = 1.Equating the coefficients, we get 4c = -20, or

c = -5.