Find the values for c and d that would make the following equation true. (cy^2)(4y^d)=-20y^3

Question

Find the values for c and d that would make the following equation true. (cy^2)(4y^d)=-20y^3

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Serenity 1 week 2021-11-26T04:31:49+00:00 1 Answer 0

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    2021-11-26T04:33:44+00:00

    Answer:

    c = -5 and d = 1

    Step-by-step explanation:

    First, multiply out (cy^2)(4y^d).  We get:  4cy^(2+d).

    We equate this result to the right side of the equation:  – 20y^3.

    Then, equating the exponents and solving for d, we get:  2 + d = 3, or d = 1.

    Equating the coefficients, we get 4c = -20, or c = -5.

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