Find the vertex. x^2+16x+8 vertex: (-8,-56).

Question

Find the vertex.

x^2+16x+8

vertex: (-8,-56).

in progress 0
Ivy 1 week 2021-09-09T10:29:38+00:00 2 Answers 0

Answers ( )

  1. Emma
    0
    2021-09-09T10:30:47+00:00

    Answer:

    The vertex is at (-8, -56).

    Step-by-step explanation:

    x^2+16x+8

    = (x + 8)^2 – 64 + 8

    = (x + 8) – 56.

    The vertex is at (-8, -56).

  2. Emma
    0
    2021-09-09T10:31:24+00:00

    Step-by-step explanation:

    x² + 16x + 8

    Complete the square.  Take half of b, square it, then add and subtract.

    (16/2)² = 8² = 64

    x² + 16x + 64 − 64 + 8

    x² + 16x + 64 − 56

    (x + 8)² − 56

    The vertex is (-8, -56).

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )