Find the vertex. x^2+16x+8 vertex: (-8,-56). Question Find the vertex. x^2+16x+8 vertex: (-8,-56). in progress 0 Math Ivy 1 week 2021-09-09T10:29:38+00:00 2021-09-09T10:29:38+00:00 2 Answers 0

## Answers ( )

Answer:The vertex is at (-8, -56).Step-by-step explanation:x^2+16x+8

= (x + 8)^2 – 64 + 8

= (x + 8) – 56.

The vertex is at (-8, -56).

Step-by-step explanation:x² + 16x + 8

Complete the square. Take half of b, square it, then add and subtract.

(16/2)² = 8² = 64

x² + 16x + 64 − 64 + 8

x² + 16x + 64 − 56

(x + 8)² − 56

The vertex is (-8, -56).