Find three consecutive even integers such that the sum is of the least and the middle is 48 more than the greatest

Question

Find three consecutive even integers such that the sum is of the least and the middle is 48 more than the greatest

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Adalynn 2 weeks 2021-10-13T22:46:47+00:00 1 Answer 0

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    2021-10-13T22:47:50+00:00

    Answer:

    50, 52, and 54

    Step-by-step explanation:

    The three even integers are x, x+2, and x+4.  The sum of the least two is 48 more than the greatest:

    x + x+2 = x+4 + 48

    2x + 2 = x + 52

    x = 50

    So the three integers are 50, 52, and 54.

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