g(x) = x3 + 6×2 + 12x + 8 Determine the function’s value when x = -1 g(x) g(-1) = -3 9(-1) = 0 9(-1) = 1

Question

g(x) = x3 + 6×2 + 12x + 8
Determine the function’s value when x = -1
g(x)
g(-1) = -3
9(-1) = 0
9(-1) = 1
g(-1) = 27
64
125

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Quinn 2 weeks 2021-10-10T20:14:35+00:00 2 Answers 0

Answers ( )

    0
    2021-10-10T20:16:29+00:00

    Answer:

    The answer is C

    Step-by-step explanation:  

    I just took the test and got it right.

    Hopefully this helps you 🙂

    pls mark brainlest 😉

    0
    2021-10-10T20:16:34+00:00

    Answer:

         g(-1) = 5 – 4 = 1

    Step-by-step explanation:

    Please use ” ^ ” to denote exponentiation:  g(x) = x^3 + 6x^2 + 12x + 8.

    Substitute -1 for x in this equation:                 g(-1) = (-1)^3 + 6(-1)^2 + 12(-1) + 8

    Then:                                                            g(-1) = -1 + 6 – 12 + 8, or

                                                                         g(-1) = 5 – 4 = 1

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27:3+15-4x7+3-1=? ( )