given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2​ [h(x)]^2/f(x)

Question

given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2​

[h(x)]^2/f(x)

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Julia 1 week 2021-11-25T09:13:32+00:00 1 Answer 0

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    2021-11-25T09:15:17+00:00

    Answer:

    \frac{1}{4}

    Step-by-step explanation:

    Substitute x = 2 into both h(x) and f(x)

    h(2) = \frac{1}{2-1} = 1 ⇒ (h(2))² = 1

    f(2) = 2 + 2 = 4

    Hence

    \frac{h(x)^2}{f(x)} when x = 2

    = \frac{1}{4}

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