Identify an equation in point-slope form for the line perpendicular to y =3/4x -4 that passes through (-1, 7).

Question

Identify an equation in point-slope form for the line perpendicular to y =3/4x -4 that passes through (-1, 7).

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Emery 6 days 2021-09-12T06:10:48+00:00 1 Answer 0

Answers ( )

    0
    2021-09-12T06:12:22+00:00

    Answer:

    y – 7 = -4/3(x + 1)

    Step-by-step explanation:

    Given

    • y =3/4x -4
    • (-1, 7)

    Convert to point slope form

    y – y1 = m(x – x1)

    m: represents what the slope is

    y – 7 = -4/3(x + 1)

    Distribute -4/3

    -4/3 * x = -4/3x

    -4/3 * 1 = -4/3

    y – 7 = -4/3x – 4/3

    Add seven in both sides

    21/3 -4/3 = 17/3

    y = -4/3x + 17/2

    Answer

    linear equation: y = -4/3x + 17/2

    point-slope form: y – 7 = -4/3(x + 1)

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