Identify the radius of the circle whose equation is (x-2)^2 + (y-8)^2 = 16​

Question

Identify the radius of the circle whose equation is (x-2)^2 + (y-8)^2 = 16​

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Madelyn 2 weeks 2021-11-23T14:17:57+00:00 1 Answer 0

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    2021-11-23T14:19:36+00:00

    Answer:

    radius = 4

    Step-by-step explanation:

    The equation of a circle in standard form is

    (x – h)² + (y – k)² = r²

    where (h, k) are the coordinates of the centre and r is the radius

    (x – 2)² + (y – 8)² = 16 ← is in standard form

    with r = \sqrt{16} = 4

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