If 63  {63}^{2} = 1 + 3 + 5 + ... + k \: then \: k =

Question

If 63
 {63}^{2}  = 1 + 3 + 5 + ... + k   \: then \: k =

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Savannah 2 weeks 2021-09-10T11:28:46+00:00 1 Answer 0

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    2021-09-10T11:29:53+00:00

    Answer:

    125

    Step-by-step explanation:

    let’s see if we can find a pattern

    1 = 1 = 1^2

    1 + 3 = 4 = 2^2

    1 + 3 + 5 = 9 = 3^2

    we are starting to see a pattern here, when we add another term, we find the next integer squared.

    we can find this last number in our sequence with 2x-1.

    so in the next line we should find 4^2. if we plug 4 into 2x-1 we would expect the last term in the sum to be 7.

    1 + 3 + 5 + 7 = 16 = 4^2

    so 2*63 -1 = 126 – 1 = 125

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