If f(x) =x^2 -2x and g(x) = 6x+4 for which value of c does (f+g)(x)=0

Question

If f(x) =x^2 -2x and g(x) = 6x+4 for which value of c does (f+g)(x)=0

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Hailey 3 weeks 2021-09-25T11:48:31+00:00 1 Answer 0

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    2021-09-25T11:50:10+00:00

    Answer:

    c = -2

    Step-by-step explanation:

    The two functions are given as:

    f(x) =  x^2 – 2x

    g(x) = 6x + 4

    To find:

    (f+g)(x) = 0

    We can evaluate (f+g)(x) using the given functions.

    We know that:

    (f+g)(x) = f(x) + g(x)

    = x²- 2x + 6x + 4

    = x² + 4x + 4

    Now, we have for x = c:

    c² + 4c + 4 = 0

    x² + 2c + 2c + 4 = 0

    c(c+2) + 2(c+2) = 0

    (c+2)² = 0

    c+2 = 0

    c = -2

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