If I need to find 4 consecutive integers and the second and fourth equal 58 how do I find the first and third integers?

Question

If I need to find 4 consecutive integers and the second and fourth equal 58 how do I find the first and third integers?

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Piper 2 weeks 2021-11-20T18:13:04+00:00 2 Answers 0

Answers ( )

    0
    2021-11-20T18:14:07+00:00

    Answer: 27, 29

    Step-by-step explanation:

    Consecutive integers are as follows:

    First Integer: x

    Second Integer: x + 1

    Third Integer: x + 2

    Fourth Integer: x + 3

    The second and fourth = 58

            x + 1    +      x + 3    = 58

                               2x + 4 = 58

                               2x       = 54

                                 x       = 27

    First Integer:  x              = 27

    Third Integer: x + 2       = 27 + 2      = 29

    0
    2021-11-20T18:15:02+00:00

    Answer:

    27, 29

    Step-by-step explanation:

    n, n + 1, n + 2, n + 3 – four consecutive integers

    The equation:

    (n + 1) + (n + 3) = 58

    n + 1 + n + 3 = 58                combine like terms

    (n + n) + (1 + 3) = 58

    2n + 4 = 58             subtract 4 from both sides

    2n = 54            divide both sides by 2

    n = 27 – first

    n + 1 = 28 – second

    n + 2 = 29 – third

    n + 3 = 30 – fourth

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27:3+15-4x7+3-1=? ( )