if x varies jointly as y and z,and x=8 when y=4 and a=9,find z when x=16 and y=6​

Question

if x varies jointly as y and z,and x=8 when y=4 and a=9,find z when x=16 and y=6​

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Kennedy 1 week 2021-10-13T23:59:09+00:00 1 Answer 0

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    2021-10-14T00:00:25+00:00

    Answer:

    z=12

    Step-by-step explanation:

    It is given that x varies jointly as y and z, it means

    x\propto yz

    x=kyz

    x(y,z)=kyz

    where, k is the constant of proportionality.

    It is given that x=8 when y=4 and z=9

    (8)=k(4)(9)

    8=36k

    Divide both sides by 36.

    \frac{8}{36}=k

    \frac{2}{9}=k

    The value of k is 2/9.

    x=\frac{2}{9}yz

    We need to find the value of z when x=16 and y=6​.

    Substitute x=16 and y=6 in the above equation.

    16=\frac{2}{9}(6)z

    16=\frac{4}{3}z

    Multiply both sides by 3.

    48=4z

    Divide both sides by 4.

    12=z

    Therefore, the value of z is 12.

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