If you are given the graph of h(x)=log(6)x, how could you graph m(x)=log(6)(x+3)? Translate each point of the graph of h(x) 3 units up. Tran

Question

If you are given the graph of h(x)=log(6)x, how could you graph m(x)=log(6)(x+3)? Translate each point of the graph of h(x) 3 units up. Translate each point of the graph of h(x) 3 units down. Translate each point of the graph of h(x) 3 units right. Translate each point of the graph of h(x) 3 units left.

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5 days 2021-09-13T15:20:40+00:00 2 Answers 0

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    0
    2021-09-13T15:22:15+00:00

    Answer:

    Last option: Translate each point of the graph of h(x) 3 units left.

    Step-by-step explanation:

    There are some transformations for a function f(x). The following is one of these transformations:

    If f(x+k), then the function is shifted “k” units to the left.

    Given the function  h(x)=log_6(x) and the function  m(x)=log_6(x+3), you can notice that the function m(x) is the function h(x) but shifted left 3 units.

    Therefore, you could graph the function m(x) by translating each point of the graph of the function h(x) 3 units left.

    This matches with the last option.

    0
    2021-09-13T15:22:17+00:00

    Answer:

    Last option (D) Translate each point of the graph of h(x) 3 units left.

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