In the equation, p and t are constants. What is the value of p? 4×2 − 9 = (px + t)(px − t) A) 2 B) 3 C) 4 D) 9

Question

In the equation, p and t are constants. What is the value of p? 4×2 − 9 = (px + t)(px − t) A) 2 B) 3 C) 4 D) 9

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Elliana 1 week 2021-10-11T19:11:00+00:00 2 Answers 0

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    0
    2021-10-11T19:12:31+00:00

    The value of p should be 2.

    Given that,

    • P and t are constants.

    And,

    • 4x^2 - 9 = (px + t) (px - t)\

    Now we use the following formula to determine the value of p

    We know that

    a^2 - b^2 = (a - b) (a + b)\\\\4x^2 - 9 = (2x)^2 - 3^2 = (2x -3) (2x + 3)

    Thus,

    (px + t ) (px – t) = (2x – 3) (2x + 3)

    So, here p = 2, and t = 3

    Therefore we can conclude that the value of p is 2

    Learn more about the algebraic equations here: brainly.com/question/12694668

    0
    2021-10-11T19:12:42+00:00

    Answer:

    A) 2

    Step-by-step explanation:

    4x² – 9 = (px + t)(px – t)

    Using formula a² – b² = (a-b)(a+b)

    4x² – 9 = (2x)² – 3² = (2x – 3)(2x+3),

    so

    (px + t)(px – t) = (2x – 3)(2x + 3).

    We can see that p = 2, and t = 3.

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