In the parabola y = (x + 12 + 2, what is the vertex?

Question

In the parabola y = (x + 12 + 2, what is the vertex?

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Aaliyah 7 days 2021-09-10T09:39:45+00:00 1 Answer 0

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    2021-09-10T09:41:21+00:00

    Answer:

    The vertex is the point (-6,-34)

    Step-by-step explanation:

    we know that

    The equation of a vertical parabola into vertex form is equal to

    y=a(x-h)^{2}+k

    where

    (h,k) is the vertex of the parabola

    In this problem we have

    y=x^{2}+12x+2

    Convert in vertex form

    Group terms that contain the same variable, and move the constant to the opposite side of the equation

    y-2=x^{2}+12x

    Complete the square . Remember to balance the equation by adding the same constants to each side.

    y-2+36=x^{2}+12x+36

    y+34=x^{2}+12x+36

    Rewrite as perfect squares

    y+34=(x+6)^{2}

    y=(x+6)^{2}-34

    The vertex is the point (-6,-34)

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