in triangle ABC, angle A = 45, c= 17, and angle B = 25. Find a to the nearest tenth.

Question

in triangle ABC, angle A = 45, c= 17, and angle B = 25. Find a to the nearest tenth.

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Kennedy 1 week 2021-09-15T17:21:51+00:00 2 Answers 0

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    0
    2021-09-15T17:23:33+00:00

    Answer:

    find the sines of each angle. Sin of 45 is .70710 Sin of 25 is .422618 and Sin of 17 is .29237. Then multiply these numbers by the reciprocal of the smallest sides.Smallest side is .29237 so divide that by 1. You get 3.42032. Multiply 3.42032 with the other remaining numbers (.70710 and .422618) and you will get your sides. 3.42032 times .70710 is 2.418 which rounds to 2.4 🙂

    Step-by-step explanation:

    0
    2021-09-15T17:23:39+00:00

    Answer:

    The answer would be 12.8

    Step-by-step explanation:

    I looked it up and found the answer on another website

    it is 12.8

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27:3+15-4x7+3-1=? ( )