Jon has to choose which variable to solve for in order to be able to do the problem below in the most efficient manner. 6x + 3y

Question

Jon has to choose which variable to solve for in order to be able to do the problem below in the most efficient manner.

6x + 3y = 27 5x+ 2y + 21

Which variable should he choose so that he can use substitution to solve the system?
Jon should solve for y in the first equation because the coefficients can be reduced by a common factor to eliminate the coefficient for y.
Jon should solve for x in the first equation because the coefficients can be reduced by a common factor to eliminate the coefficient for x.
Jon should solve for y in the second equation because the coefficients can be reduced by a common factor to eliminate the coefficient for y.
Jon should solve for x in the second equation because the coefficients can be reduced by a common factor to eliminate the coefficient for x.

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Ivy 2 weeks 2021-11-21T12:27:23+00:00 2 Answers 0

Answers ( )

    0
    2021-11-21T12:28:25+00:00

    Answer:

    The most efficient variable to solve for is y in the first equation because all of the terms have a common factor of 3.

    Step-by-step explanation:

    0
    2021-11-21T12:29:00+00:00

    The most efficient way to solve this problem is isolating the y in the first equation because:

    6x + 3y = 27

    3y = 27 – 6x

    y = 9 – 2x

    Since all the numbers have a common factor of 3, it can be easily simplified/reduce.

    If you used any other variable, you would have gotten a fraction.

    Now that you found y, you can substitute it into the other equation to solve for x.  

    ANYWAYS, your answer is A

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