Let the sample space be S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose the outcomes are equally likely. Compute the probability of the event E

Question

Let the sample space be S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose the outcomes are equally likely. Compute the probability of the event E = ​”an odd number less than 7​.”

in progress 0
Evelyn 2 weeks 2021-10-11T22:11:24+00:00 1 Answer 0

Answers ( )

    0
    2021-10-11T22:13:02+00:00

    Answer:

    The probability is 3/5

    Step-by-step explanation:

    Given,

    Sample space, S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10},

    ⇒ n(S) = 10,

    Odd numbers less than 7 = 1, 2, 3, 4, 5 and 6

    i.e. E = {1, 2, 3, 4, 5, 6}

    ⇒ n(E) = 6,

    \because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

    So, the probability of the event E,

    P(E) =\frac{n(E)}{n(S)}

    =\frac{6}{10}

    =\frac{3}{5}

Leave an answer

Browse
Browse

27:3+15-4x7+3-1=? ( )