On a given school day, the probability that Nick oversleeps is 48% and the probability he has a pop quiz is 25%. Assuming these two ev

Question

On a given school day, the probability that Nick oversleeps is 48% and the probability he has a pop quiz
is 25%. Assuming these two events are independent, what is the probability that Nick oversleeps and has
pop quiz on the same day?

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Arianna 1 day 2021-10-12T11:12:20+00:00 1 Answer 0

Answers ( )

    0
    2021-10-12T11:14:14+00:00

    Answer:

    0.12

    Step-by-step explanation:

    Independent events are when probability of one event happening doesn’t affect the probability of the other event happening.

    Also,

    In probability “AND” means “multiplication” and “OR” means “addition”.

    The question asks for probability that Nick oversleeps “AND” has pop quiz. So we need to multiply the individual probabilities (since independent, they have no affect on each other).

    P(Nick oversleeps) = 0.48

    P(pop quiz) = 0.25

    Thus,

    P(Nick oversleeps AND pop quiz) = 0.48 * 0.25 = 0.12

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