PLEASE help me out ! A spinner has 10 equally sized sections, 6 of which are gray and 4 of which are blue. The spinner is spun twice.

Question

PLEASE help me out !
A spinner has 10 equally sized sections, 6 of which are gray and 4 of which are blue. The spinner is spun twice. What is the probability that the first spin lands on blue and the second spin lands on gray? Write your answer as a fraction in simplest form.

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1 week 2021-11-23T12:13:50+00:00 2 Answers 0

Answers ( )

  1. Emma
    0
    2021-11-23T12:15:04+00:00

    Answer:6/25

    Step-by-step explanation:

  2. Emma
    0
    2021-11-23T12:15:30+00:00

    Answer:

    6/25

    Step-by-step explanation:

    To solve this we first need to know the probability for landing on a gray section and the probability of landing on a blue section:

    Probability of gray – 6/10 or 3/5

    Probability of blue – 4/10 or 2/5

    Now that we know this, the question asked us to find the probability we will spin blue and than gray. We know that these events are independent of each other meaning that one outcome will not affect the probability of another outcome. Therefore in order to find the probability of blue then gray we can just multiply the probability of landing on gray (3/5) by the probability of landing on blue (2/5).

    3/5 x 2/5 = 6/25

    I hope this helps!

    -The Business Man

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