PLS HELP RN 1. What is the value of 4k + 6 (j – 2) when k = 3 and j = 5? 2. 9(r – 5) = 4r – 5

Question

PLS HELP RN
1. What is the value of 4k + 6 (j – 2) when k = 3 and j = 5?
2. 9(r – 5) = 4r – 5

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Eliza 3 days 2021-09-13T14:58:25+00:00 1 Answer 0

Answers ( )

    0
    2021-09-13T15:00:02+00:00

    Answer:

    1.

    4k + 6(j – 2)

    Substitute the values.

    4(3) + 6 [(5) – 2]

    12 + 6 (3)

    12 + 18

    = 30

    2.

    9(r – 5) = 4r – 5

    9r – 45 = 4r – 5

    9r – 4r – 45 = -5

    5r – 45 = -5

    5r = -5 + 45

    5r = 40

    r = 40 รท 5

    r = 8

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