sally has a pet snail that fell into a well the well is 16 feet deep each day the snail climbs up 5 feet but each night it slides back diown

Question

sally has a pet snail that fell into a well the well is 16 feet deep each day the snail climbs up 5 feet but each night it slides back diown 4 feet how many days will it take for sallys snail to get to the top of the well

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Amaya 1 week 2021-10-11T20:23:03+00:00 1 Answer 0

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    2021-10-11T20:24:51+00:00

    Answer:

    12 days

    Step-by-step explanation:

    Sally has  pet snail that fell into a well.

    Depth of the well = 16 feet

    Snail climbs up 5 feet but each night it slides back down 4 feet.

    So the snail climbs up per day = 5 feet – 4 feet = 1 feet.

    Number of days snail took to reach at 11 feet = 11 × 1 = 11 feet

    Remaining distance to cover by the snail = 16 – 11 = 5 feet

    Number of days to cover remaining 5 feet to reach the top of the well = 1 day

    Therefore, snail will take 12 days to reach the top of the well.

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